4a^2-19=0

Solution for 4a^2-19=0 equation:

4a^2-19=0

a = 4; b = 0; c = -19;
Δ = b2-4ac
Δ = 02-4·4·(-19)
Δ = 304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{304}=\sqrt{16*19}=\sqrt{16}*\sqrt{19}=4\sqrt{19}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{19}}{2*4}=\frac{0-4\sqrt{19}}{8}
=-\frac{4\sqrt{19}}{8}
=-\frac{\sqrt{19}}{2}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{19}}{2*4}=\frac{0+4\sqrt{19}}{8}
=\frac{4\sqrt{19}}{8}
=\frac{\sqrt{19}}{2}
$